5b^2-41=41

Solution for 5b^2-41=41 equation:

5b^2-41=41

We move all terms to the left:

5b^2-41-(41)=0

We add all the numbers together, and all the variables

5b^2-82=0

a = 5; b = 0; c = -82;
Δ = b2-4ac
Δ = 02-4·5·(-82)
Δ = 1640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1640}=\sqrt{4*410}=\sqrt{4}*\sqrt{410}=2\sqrt{410}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{410}}{2*5}=\frac{0-2\sqrt{410}}{10}
=-\frac{2\sqrt{410}}{10}
=-\frac{\sqrt{410}}{5}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{410}}{2*5}=\frac{0+2\sqrt{410}}{10}
=\frac{2\sqrt{410}}{10}
=\frac{\sqrt{410}}{5}
$